Fundamental Theorem of Calculus – AP Calculus AB

1. By FTC Part 1: d/dx [∫₀ˣ sin(t) dt] = ?

cos(x) sin(x) -cos(x) -sin(x)

2. ∫₀² x² dx = F(2) - F(0), where F(x) = x³/3. The value is:

4 8/3 2 4/3

3. What does a negative definite integral value represent?

The function has no antiderivative Area below the x-axis exceeds area above The interval [a,b] is negative An error occurred in computation